7(z-5)+1=2-3(2z-1)

Solution for 7(z-5)+1=2-3(2z-1) equation:

7(z-5)+1=2-3(2z-1)

We simplify the equation to the form, which is simple to understand 
7(z-5)+1=2-3(2z-1)

Reorder the terms in parentheses
+(+7z-35)+1=2-3*(2z-1)

Remove unnecessary parentheses
+7z-35+1=+2-3+*(+2z-1+)

Reorder the terms in parentheses
+7z-35+1=2+(-6z+3)

Remove unnecessary parentheses
+7z-35+1=+2-6z+3

We move all terms containing z to the left and all other terms to the right. 
+7z+6z=+2+3+35-1

We simplify left and right side of the equation. 
+13z=+39

We divide both sides of the equation by 13 to get z. 
z=3