7(z-5)-6(2-3z)=12(Z+1)

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Solution for 7(z-5)-6(2-3z)=12(Z+1) equation:


Simplifying
7(z + -5) + -6(2 + -3z) = 12(Z + 1)

Reorder the terms:
7(-5 + z) + -6(2 + -3z) = 12(Z + 1)
(-5 * 7 + z * 7) + -6(2 + -3z) = 12(Z + 1)
(-35 + 7z) + -6(2 + -3z) = 12(Z + 1)
-35 + 7z + (2 * -6 + -3z * -6) = 12(Z + 1)
-35 + 7z + (-12 + 18z) = 12(Z + 1)

Reorder the terms:
-35 + -12 + 7z + 18z = 12(Z + 1)

Combine like terms: -35 + -12 = -47
-47 + 7z + 18z = 12(Z + 1)

Combine like terms: 7z + 18z = 25z
-47 + 25z = 12(Z + 1)

Reorder the terms:
-47 + 25z = 12(1 + Z)
-47 + 25z = (1 * 12 + Z * 12)
-47 + 25z = (12 + 12Z)

Solving
-47 + 25z = 12 + 12Z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '47' to each side of the equation.
-47 + 47 + 25z = 12 + 47 + 12Z

Combine like terms: -47 + 47 = 0
0 + 25z = 12 + 47 + 12Z
25z = 12 + 47 + 12Z

Combine like terms: 12 + 47 = 59
25z = 59 + 12Z

Divide each side by '25'.
z = 2.36 + 0.48Z

Simplifying
z = 2.36 + 0.48Z

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