7*((1-2z)/3)+5z=-2

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Solution for 7*((1-2z)/3)+5z=-2 equation: 


z in (-oo:+oo)

7*((1-(2*z))/3)+5*z = -2 // + 2

7*((1-(2*z))/3)+5*z+2 = 0

7*((1-2*z)/3)+5*z+2 = 0

(7*(1-2*z))/3+5*z+2 = 0

(7*(1-2*z))/3+(3*5*z)/3+(2*3)/3 = 0

7*(1-2*z)+3*5*z+2*3 = 0

z+6+7 = 0

z+13 = 0

(z+13)/3 = 0

(z+13)/3 = 0 // * 3

z+13 = 0

z+13 = 0 // - 13

z = -13

z = -13

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