7*(3-2x)+3x=x+4*(x-1)

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Solution for 7*(3-2x)+3x=x+4*(x-1) equation: 



7(3-2x)+3x=x+4(x-1)

We move all terms to the left:

7(3-2x)+3x-(x+4(x-1))=0

We add all the numbers together, and all the variables

7(-2x+3)+3x-(x+4(x-1))=0

We add all the numbers together, and all the variables

3x+7(-2x+3)-(x+4(x-1))=0

We multiply parentheses

3x-14x-(x+4(x-1))+21=0



We calculate terms in parentheses: -(x+4(x-1)), so:

x+4(x-1)

We multiply parentheses

x+4x-4

We add all the numbers together, and all the variables

5x-4

Back to the equation:

-(5x-4)



We add all the numbers together, and all the variables

-11x-(5x-4)+21=0

We get rid of parentheses

-11x-5x+4+21=0

We add all the numbers together, and all the variables

-16x+25=0

We move all terms containing x to the left, all other terms to the right

-16x=-25

x=-25/-16

x=1+9/16

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