7*(4x-8)-12-4x=9x-(7x+6)

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Solution for 7*(4x-8)-12-4x=9x-(7x+6) equation: 



7*(4x-8)-12-4x=9x-(7x+6)

We move all terms to the left:

7*(4x-8)-12-4x-(9x-(7x+6))=0

We add all the numbers together, and all the variables

-4x+7*(4x-8)-(9x-(7x+6))-12=0

We multiply parentheses

-4x+28x-(9x-(7x+6))-56-12=0



We calculate terms in parentheses: -(9x-(7x+6)), so:

9x-(7x+6)

We get rid of parentheses

9x-7x-6

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We add all the numbers together, and all the variables

24x-(2x-6)-68=0

We get rid of parentheses

24x-2x+6-68=0

We add all the numbers together, and all the variables

22x-62=0

We move all terms containing x to the left, all other terms to the right

22x=62

x=62/22

x=2+9/11

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