7*(6z-1)+3*(2z+1)-5*(12z-7)=23

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Solution for 7*(6z-1)+3*(2z+1)-5*(12z-7)=23 equation: 



7(6z-1)+3(2z+1)-5(12z-7)=23

We move all terms to the left:

7(6z-1)+3(2z+1)-5(12z-7)-(23)=0

We multiply parentheses

42z+6z-60z-7+3+35-23=0

We add all the numbers together, and all the variables

-12z+8=0

We move all terms containing z to the left, all other terms to the right

-12z=-8

z=-8/-12

z=2/3

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