7+(-8z+2)=(7z+5)+1

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Solution for 7+(-8z+2)=(7z+5)+1 equation: 



7+(-8z+2)=(7z+5)+1

We move all terms to the left:

7+(-8z+2)-((7z+5)+1)=0

We get rid of parentheses

-8z-((7z+5)+1)+2+7=0



We calculate terms in parentheses: -((7z+5)+1), so:

(7z+5)+1

We get rid of parentheses

7z+5+1

We add all the numbers together, and all the variables

7z+6

Back to the equation:

-(7z+6)



We add all the numbers together, and all the variables

-8z-(7z+6)+9=0

We get rid of parentheses

-8z-7z-6+9=0

We add all the numbers together, and all the variables

-15z+3=0

We move all terms containing z to the left, all other terms to the right

-15z=-3

z=-3/-15

z=1/5

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