7+(2x-3)/3=8x/5

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Solution for 7+(2x-3)/3=8x/5 equation:


x in (-oo:+oo)

(2*x-3)/3+7 = (8*x)/5 // - (8*x)/5

(2*x-3)/3-((8*x)/5)+7 = 0

(2*x-3)/3+(-8/5)*x+7 = 0

(2*x-3)/3+(-8*x)/5+7 = 0

(5*(2*x-3))/(3*5)+(-8*3*x)/(3*5)+(3*5*7)/(3*5) = 0

5*(2*x-3)-8*3*x+3*5*7 = 0

105-14*x-15 = 0

90-14*x = 0

(90-14*x)/(3*5) = 0

(90-14*x)/(3*5) = 0 // * 3*5

90-14*x = 0

90-14*x = 0 // - 90

-14*x = -90 // : -14

x = -90/(-14)

x = 45/7

x = 45/7

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