7+(3x-5)=10x+(8x-1)

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Solution for 7+(3x-5)=10x+(8x-1) equation: 



7+(3x-5)=10x+(8x-1)

We move all terms to the left:

7+(3x-5)-(10x+(8x-1))=0

We get rid of parentheses

3x-(10x+(8x-1))-5+7=0



We calculate terms in parentheses: -(10x+(8x-1)), so:

10x+(8x-1)

We get rid of parentheses

10x+8x-1

We add all the numbers together, and all the variables

18x-1

Back to the equation:

-(18x-1)



We add all the numbers together, and all the variables

3x-(18x-1)+2=0

We get rid of parentheses

3x-18x+1+2=0

We add all the numbers together, and all the variables

-15x+3=0

We move all terms containing x to the left, all other terms to the right

-15x=-3

x=-3/-15

x=1/5

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