7+(3z-8)=8+z

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Solution for 7+(3z-8)=8+z equation: 



7+(3z-8)=8+z

We move all terms to the left:

7+(3z-8)-(8+z)=0

We add all the numbers together, and all the variables

(3z-8)-(z+8)+7=0

We get rid of parentheses

3z-z-8-8+7=0

We add all the numbers together, and all the variables

2z-9=0

We move all terms containing z to the left, all other terms to the right

2z=9

z=9/2

z=4+1/2

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