7+(4x-31)=22x-(60+6x)

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Solution for 7+(4x-31)=22x-(60+6x) equation: 



7+(4x-31)=22x-(60+6x)

We move all terms to the left:

7+(4x-31)-(22x-(60+6x))=0

We add all the numbers together, and all the variables

(4x-31)-(22x-(6x+60))+7=0

We get rid of parentheses

4x-(22x-(6x+60))-31+7=0



We calculate terms in parentheses: -(22x-(6x+60)), so:

22x-(6x+60)

We get rid of parentheses

22x-6x-60

We add all the numbers together, and all the variables

16x-60

Back to the equation:

-(16x-60)



We add all the numbers together, and all the variables

4x-(16x-60)-24=0

We get rid of parentheses

4x-16x+60-24=0

We add all the numbers together, and all the variables

-12x+36=0

We move all terms containing x to the left, all other terms to the right

-12x=-36

x=-36/-12

x=+3

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