7+(4y-3)=28

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Solution for 7+(4y-3)=28 equation: 



7+(4y-3)=28

We move all terms to the left:

7+(4y-3)-(28)=0

We add all the numbers together, and all the variables

(4y-3)-21=0

We get rid of parentheses

4y-3-21=0

We add all the numbers together, and all the variables

4y-24=0

We move all terms containing y to the left, all other terms to the right

4y=24

y=24/4

y=6

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