7+1(b+-4)=(7+b)+-4

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Solution for 7+1(b+-4)=(7+b)+-4 equation: 



7+1(b+-4)=(7+b)+-4

We move all terms to the left:

7+1(b+-4)-((7+b)+-4)=0

We add all the numbers together, and all the variables

1(b-4)-((b+7)+-4)+7=0

We use the square of the difference formula

1(b-4)-((b+7)-4)+7=0



We calculate terms in parentheses: -((b+7)-4), so:

(b+7)-4

We get rid of parentheses

b+7-4

We add all the numbers together, and all the variables

b+3

Back to the equation:

-(b+3)



We get rid of parentheses

1(b-4)-b-3+7=0

We add all the numbers together, and all the variables

-1b+1(b-4)+4=0

We move all terms containing b to the left, all other terms to the right

-1b+1(b-4)=-4

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