7+1/5x0

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Solution for 7+1/5x0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/5)*x^0+7 = 0

1/5+7 = 0

36/5 = 0

x belongs to the empty set

x belongs to the empty set

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