7+1=1/2(4x-2)

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Solution for 7+1=1/2(4x-2) equation: 



7+1=1/2(4x-2)

We move all terms to the left:

7+1-(1/2(4x-2))=0



Domain of the equation: 2(4x-2))!=0

x∈R



We add all the numbers together, and all the variables

-(1/2(4x-2))+8=0

We multiply all the terms by the denominator


-(1+8*2(4x-2))=0



We calculate terms in parentheses: -(1+8*2(4x-2)), so:

1+8*2(4x-2)

determiningTheFunctionDomain
8*2(4x-2)+1

Wy multiply elements

16x(4+1

Back to the equation:

-(16x(4+1)



We add all the numbers together, and all the variables

-(16x5=0

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