7+2(2x+4)=18+3(x-1)

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Solution for 7+2(2x+4)=18+3(x-1) equation: 



7+2(2x+4)=18+3(x-1)

We move all terms to the left:

7+2(2x+4)-(18+3(x-1))=0

We multiply parentheses

4x-(18+3(x-1))+8+7=0



We calculate terms in parentheses: -(18+3(x-1)), so:

18+3(x-1)

determiningTheFunctionDomain
3(x-1)+18

We multiply parentheses

3x-3+18

We add all the numbers together, and all the variables

3x+15

Back to the equation:

-(3x+15)



We add all the numbers together, and all the variables

4x-(3x+15)+15=0

We get rid of parentheses

4x-3x-15+15=0

We add all the numbers together, and all the variables

x=0

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