7+2(2x-2)=-3(4x-3)+6x

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Solution for 7+2(2x-2)=-3(4x-3)+6x equation: 



7+2(2x-2)=-3(4x-3)+6x

We move all terms to the left:

7+2(2x-2)-(-3(4x-3)+6x)=0

We multiply parentheses

4x-(-3(4x-3)+6x)-4+7=0



We calculate terms in parentheses: -(-3(4x-3)+6x), so:

-3(4x-3)+6x

We add all the numbers together, and all the variables

6x-3(4x-3)

We multiply parentheses

6x-12x+9

We add all the numbers together, and all the variables

-6x+9

Back to the equation:

-(-6x+9)



We add all the numbers together, and all the variables

4x-(-6x+9)+3=0

We get rid of parentheses

4x+6x-9+3=0

We add all the numbers together, and all the variables

10x-6=0

We move all terms containing x to the left, all other terms to the right

10x=6

x=6/10

x=3/5

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