7+2(3c+1)=6c+9

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Solution for 7+2(3c+1)=6c+9 equation: 


Simplifying
7 + 2(3c + 1) = 6c + 9

Reorder the terms:
7 + 2(1 + 3c) = 6c + 9
7 + (1 * 2 + 3c * 2) = 6c + 9
7 + (2 + 6c) = 6c + 9

Combine like terms: 7 + 2 = 9
9 + 6c = 6c + 9

Reorder the terms:
9 + 6c = 9 + 6c

Add '-9' to each side of the equation.
9 + -9 + 6c = 9 + -9 + 6c

Combine like terms: 9 + -9 = 0
0 + 6c = 9 + -9 + 6c
6c = 9 + -9 + 6c

Combine like terms: 9 + -9 = 0
6c = 0 + 6c
6c = 6c

Add '-6c' to each side of the equation.
6c + -6c = 6c + -6c

Combine like terms: 6c + -6c = 0
0 = 6c + -6c

Combine like terms: 6c + -6c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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