7+2(3x-5)=-3(2x+1)

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Solution for 7+2(3x-5)=-3(2x+1) equation:



7+2(3x-5)=-3(2x+1)
We move all terms to the left:
7+2(3x-5)-(-3(2x+1))=0
We multiply parentheses
6x-(-3(2x+1))-10+7=0
We calculate terms in parentheses: -(-3(2x+1)), so:
-3(2x+1)
We multiply parentheses
-6x-3
Back to the equation:
-(-6x-3)
We add all the numbers together, and all the variables
6x-(-6x-3)-3=0
We get rid of parentheses
6x+6x+3-3=0
We add all the numbers together, and all the variables
12x=0
x=0/12
x=0

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