7+2(3x-7)=9-4(3x+1)

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Solution for 7+2(3x-7)=9-4(3x+1) equation: 



7+2(3x-7)=9-4(3x+1)

We move all terms to the left:

7+2(3x-7)-(9-4(3x+1))=0

We multiply parentheses

6x-(9-4(3x+1))-14+7=0



We calculate terms in parentheses: -(9-4(3x+1)), so:

9-4(3x+1)

determiningTheFunctionDomain
-4(3x+1)+9

We multiply parentheses

-12x-4+9

We add all the numbers together, and all the variables

-12x+5

Back to the equation:

-(-12x+5)



We add all the numbers together, and all the variables

6x-(-12x+5)-7=0

We get rid of parentheses

6x+12x-5-7=0

We add all the numbers together, and all the variables

18x-12=0

We move all terms containing x to the left, all other terms to the right

18x=12

x=12/18

x=2/3

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