7+2(4x-5)=9-4(2x+1)

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Solution for 7+2(4x-5)=9-4(2x+1) equation: 



7+2(4x-5)=9-4(2x+1)

We move all terms to the left:

7+2(4x-5)-(9-4(2x+1))=0

We multiply parentheses

8x-(9-4(2x+1))-10+7=0



We calculate terms in parentheses: -(9-4(2x+1)), so:

9-4(2x+1)

determiningTheFunctionDomain
-4(2x+1)+9

We multiply parentheses

-8x-4+9

We add all the numbers together, and all the variables

-8x+5

Back to the equation:

-(-8x+5)



We add all the numbers together, and all the variables

8x-(-8x+5)-3=0

We get rid of parentheses

8x+8x-5-3=0

We add all the numbers together, and all the variables

16x-8=0

We move all terms containing x to the left, all other terms to the right

16x=8

x=8/16

x=1/2

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