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7+2(5x-6)=5-4(2x+1)
We move all terms to the left:
7+2(5x-6)-(5-4(2x+1))=0
We multiply parentheses
10x-(5-4(2x+1))-12+7=0
We calculate terms in parentheses: -(5-4(2x+1)), so:We add all the numbers together, and all the variables
5-4(2x+1)
determiningTheFunctionDomain -4(2x+1)+5
We multiply parentheses
-8x-4+5
We add all the numbers together, and all the variables
-8x+1
Back to the equation:
-(-8x+1)
10x-(-8x+1)-5=0
We get rid of parentheses
10x+8x-1-5=0
We add all the numbers together, and all the variables
18x-6=0
We move all terms containing x to the left, all other terms to the right
18x=6
x=6/18
x=1/3
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