7+2(g-3)+3(4-g)=51

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Solution for 7+2(g-3)+3(4-g)=51 equation: 



7+2(g-3)+3(4-g)=51

We move all terms to the left:

7+2(g-3)+3(4-g)-(51)=0

We add all the numbers together, and all the variables

2(g-3)+3(-1g+4)+7-51=0

We add all the numbers together, and all the variables

2(g-3)+3(-1g+4)-44=0

We multiply parentheses

2g-3g-6+12-44=0

We add all the numbers together, and all the variables

-1g-38=0

We move all terms containing g to the left, all other terms to the right

-g=38

g=38/-1

g=-38

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