7+2(j-4)=j-2j-+8

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Solution for 7+2(j-4)=j-2j-+8 equation: 



7+2(j-4)=j-2j-+8

We move all terms to the left:

7+2(j-4)-(j-2j-+8)=0

We add all the numbers together, and all the variables

2(j-4)-(-1j)+7=0

We multiply parentheses

2j-(-1j)-8+7=0

We get rid of parentheses

2j+1j-8+7=0

We add all the numbers together, and all the variables

3j-1=0

We move all terms containing j to the left, all other terms to the right

3j=1

j=1/3

j=1/3

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