7+2(j-4)=j-2j-+8

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Solution for 7+2(j-4)=j-2j-+8 equation:



7+2(j-4)=j-2j-+8
We move all terms to the left:
7+2(j-4)-(j-2j-+8)=0
We add all the numbers together, and all the variables
2(j-4)-(-1j)+7=0
We multiply parentheses
2j-(-1j)-8+7=0
We get rid of parentheses
2j+1j-8+7=0
We add all the numbers together, and all the variables
3j-1=0
We move all terms containing j to the left, all other terms to the right
3j=1
j=1/3
j=1/3

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