7+2(x+3)+3x=4(2x-1)-1

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Solution for 7+2(x+3)+3x=4(2x-1)-1 equation: 



7+2(x+3)+3x=4(2x-1)-1

We move all terms to the left:

7+2(x+3)+3x-(4(2x-1)-1)=0

We add all the numbers together, and all the variables

3x+2(x+3)-(4(2x-1)-1)+7=0

We multiply parentheses

3x+2x-(4(2x-1)-1)+6+7=0



We calculate terms in parentheses: -(4(2x-1)-1), so:

4(2x-1)-1

We multiply parentheses

8x-4-1

We add all the numbers together, and all the variables

8x-5

Back to the equation:

-(8x-5)



We add all the numbers together, and all the variables

5x-(8x-5)+13=0

We get rid of parentheses

5x-8x+5+13=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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