7+2(x-3)=4(x-5)

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Solution for 7+2(x-3)=4(x-5) equation: 



7+2(x-3)=4(x-5)

We move all terms to the left:

7+2(x-3)-(4(x-5))=0

We multiply parentheses

2x-(4(x-5))-6+7=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

2x-(4x-20)+1=0

We get rid of parentheses

2x-4x+20+1=0

We add all the numbers together, and all the variables

-2x+21=0

We move all terms containing x to the left, all other terms to the right

-2x=-21

x=-21/-2

x=10+1/2

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