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7+2/5y=2/5y-4
We move all terms to the left:
7+2/5y-(2/5y-4)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 5y-4)!=0We get rid of parentheses
y∈R
2/5y-2/5y+4+7=0
We multiply all the terms by the denominator
4*5y+7*5y+2-2=0
We add all the numbers together, and all the variables
4*5y+7*5y=0
Wy multiply elements
20y+35y=0
We add all the numbers together, and all the variables
55y=0
y=0/55
y=0
Równanie nie ma rozwiązania
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