7+2m+3(m-4)=35

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Solution for 7+2m+3(m-4)=35 equation: 



7+2m+3(m-4)=35

We move all terms to the left:

7+2m+3(m-4)-(35)=0

We add all the numbers together, and all the variables

2m+3(m-4)-28=0

We multiply parentheses

2m+3m-12-28=0

We add all the numbers together, and all the variables

5m-40=0

We move all terms containing m to the left, all other terms to the right

5m=40

m=40/5

m=8

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