7+2n-4=2(n-6)+15

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Solution for 7+2n-4=2(n-6)+15 equation: 



7+2n-4=2(n-6)+15

We move all terms to the left:

7+2n-4-(2(n-6)+15)=0

We add all the numbers together, and all the variables

2n-(2(n-6)+15)+3=0



We calculate terms in parentheses: -(2(n-6)+15), so:

2(n-6)+15

We multiply parentheses

2n-12+15

We add all the numbers together, and all the variables

2n+3

Back to the equation:

-(2n+3)



We get rid of parentheses

2n-2n-3+3=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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