7+3(2u-3)=-4(2u-4)+2u

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Solution for 7+3(2u-3)=-4(2u-4)+2u equation: 



7+3(2u-3)=-4(2u-4)+2u

We move all terms to the left:

7+3(2u-3)-(-4(2u-4)+2u)=0

We multiply parentheses

6u-(-4(2u-4)+2u)-9+7=0



We calculate terms in parentheses: -(-4(2u-4)+2u), so:

-4(2u-4)+2u

We add all the numbers together, and all the variables

2u-4(2u-4)

We multiply parentheses

2u-8u+16

We add all the numbers together, and all the variables

-6u+16

Back to the equation:

-(-6u+16)



We add all the numbers together, and all the variables

6u-(-6u+16)-2=0

We get rid of parentheses

6u+6u-16-2=0

We add all the numbers together, and all the variables

12u-18=0

We move all terms containing u to the left, all other terms to the right

12u=18

u=18/12

u=1+1/2

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