7+3(2x-5)=(3x+7)

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Solution for 7+3(2x-5)=(3x+7) equation:



7+3(2x-5)=(3x+7)
We move all terms to the left:
7+3(2x-5)-((3x+7))=0
We multiply parentheses
6x-((3x+7))-15+7=0
We calculate terms in parentheses: -((3x+7)), so:
(3x+7)
We get rid of parentheses
3x+7
Back to the equation:
-(3x+7)
We add all the numbers together, and all the variables
6x-(3x+7)-8=0
We get rid of parentheses
6x-3x-7-8=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5

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