7+3(2x-5)=(3x+7)

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Solution for 7+3(2x-5)=(3x+7) equation: 



7+3(2x-5)=(3x+7)

We move all terms to the left:

7+3(2x-5)-((3x+7))=0

We multiply parentheses

6x-((3x+7))-15+7=0



We calculate terms in parentheses: -((3x+7)), so:

(3x+7)

We get rid of parentheses

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

6x-(3x+7)-8=0

We get rid of parentheses

6x-3x-7-8=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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