7+3(2x-5)=2(x-9)+38

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Solution for 7+3(2x-5)=2(x-9)+38 equation: 



7+3(2x-5)=2(x-9)+38

We move all terms to the left:

7+3(2x-5)-(2(x-9)+38)=0

We multiply parentheses

6x-(2(x-9)+38)-15+7=0



We calculate terms in parentheses: -(2(x-9)+38), so:

2(x-9)+38

We multiply parentheses

2x-18+38

We add all the numbers together, and all the variables

2x+20

Back to the equation:

-(2x+20)



We add all the numbers together, and all the variables

6x-(2x+20)-8=0

We get rid of parentheses

6x-2x-20-8=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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