7+3(4v-1)=-2(3v-4)+4v

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Solution for 7+3(4v-1)=-2(3v-4)+4v equation: 



7+3(4v-1)=-2(3v-4)+4v

We move all terms to the left:

7+3(4v-1)-(-2(3v-4)+4v)=0

We multiply parentheses

12v-(-2(3v-4)+4v)-3+7=0



We calculate terms in parentheses: -(-2(3v-4)+4v), so:

-2(3v-4)+4v

We add all the numbers together, and all the variables

4v-2(3v-4)

We multiply parentheses

4v-6v+8

We add all the numbers together, and all the variables

-2v+8

Back to the equation:

-(-2v+8)



We add all the numbers together, and all the variables

12v-(-2v+8)+4=0

We get rid of parentheses

12v+2v-8+4=0

We add all the numbers together, and all the variables

14v-4=0

We move all terms containing v to the left, all other terms to the right

14v=4

v=4/14

v=2/7

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