7+3(4x-8)=109

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Solution for 7+3(4x-8)=109 equation: 



7+3(4x-8)=109

We move all terms to the left:

7+3(4x-8)-(109)=0

We add all the numbers together, and all the variables

3(4x-8)-102=0

We multiply parentheses

12x-24-102=0

We add all the numbers together, and all the variables

12x-126=0

We move all terms containing x to the left, all other terms to the right

12x=126

x=126/12

x=10+1/2

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