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7+3(5x-6)=9-5(2x+1)
We move all terms to the left:
7+3(5x-6)-(9-5(2x+1))=0
We multiply parentheses
15x-(9-5(2x+1))-18+7=0
We calculate terms in parentheses: -(9-5(2x+1)), so:We add all the numbers together, and all the variables
9-5(2x+1)
determiningTheFunctionDomain -5(2x+1)+9
We multiply parentheses
-10x-5+9
We add all the numbers together, and all the variables
-10x+4
Back to the equation:
-(-10x+4)
15x-(-10x+4)-11=0
We get rid of parentheses
15x+10x-4-11=0
We add all the numbers together, and all the variables
25x-15=0
We move all terms containing x to the left, all other terms to the right
25x=15
x=15/25
x=3/5
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