7+3(6x-4)=-41

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Solution for 7+3(6x-4)=-41 equation: 



7+3(6x-4)=-41

We move all terms to the left:

7+3(6x-4)-(-41)=0

We add all the numbers together, and all the variables

3(6x-4)+48=0

We multiply parentheses

18x-12+48=0

We add all the numbers together, and all the variables

18x+36=0

We move all terms containing x to the left, all other terms to the right

18x=-36

x=-36/18

x=-2

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