7+3(7+x)=-2(x+1)+7x

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Solution for 7+3(7+x)=-2(x+1)+7x equation: 



7+3(7+x)=-2(x+1)+7x

We move all terms to the left:

7+3(7+x)-(-2(x+1)+7x)=0

We add all the numbers together, and all the variables

3(x+7)-(-2(x+1)+7x)+7=0

We multiply parentheses

3x-(-2(x+1)+7x)+21+7=0



We calculate terms in parentheses: -(-2(x+1)+7x), so:

-2(x+1)+7x

We add all the numbers together, and all the variables

7x-2(x+1)

We multiply parentheses

7x-2x-2

We add all the numbers together, and all the variables

5x-2

Back to the equation:

-(5x-2)



We add all the numbers together, and all the variables

3x-(5x-2)+28=0

We get rid of parentheses

3x-5x+2+28=0

We add all the numbers together, and all the variables

-2x+30=0

We move all terms containing x to the left, all other terms to the right

-2x=-30

x=-30/-2

x=+15

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