7+3(x+1)=x-4(2+x)

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Solution for 7+3(x+1)=x-4(2+x) equation: 



7+3(x+1)=x-4(2+x)

We move all terms to the left:

7+3(x+1)-(x-4(2+x))=0

We add all the numbers together, and all the variables

3(x+1)-(x-4(x+2))+7=0

We multiply parentheses

3x-(x-4(x+2))+3+7=0



We calculate terms in parentheses: -(x-4(x+2)), so:

x-4(x+2)

We multiply parentheses

x-4x-8

We add all the numbers together, and all the variables

-3x-8

Back to the equation:

-(-3x-8)



We add all the numbers together, and all the variables

3x-(-3x-8)+10=0

We get rid of parentheses

3x+3x+8+10=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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