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7+3/5x=7/10x
We move all terms to the left:
7+3/5x-(7/10x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/5x-(+7/10x)+7=0
We get rid of parentheses
3/5x-7/10x+7=0
We calculate fractions
30x/50x^2+(-35x)/50x^2+7=0
We multiply all the terms by the denominator
30x+(-35x)+7*50x^2=0
Wy multiply elements
350x^2+30x+(-35x)=0
We get rid of parentheses
350x^2+30x-35x=0
We add all the numbers together, and all the variables
350x^2-5x=0
a = 350; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·350·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*350}=\frac{0}{700} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*350}=\frac{10}{700} =1/70 $
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