7+3/5y=2/5y-4

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Solution for 7+3/5y=2/5y-4 equation: 



7+3/5y=2/5y-4

We move all terms to the left:

7+3/5y-(2/5y-4)=0



Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R





Domain of the equation: 5y-4)!=0

y∈R



We get rid of parentheses

3/5y-2/5y+4+7=0

We multiply all the terms by the denominator


4*5y+7*5y+3-2=0

We add all the numbers together, and all the variables

4*5y+7*5y+1=0

Wy multiply elements

20y+35y+1=0

We add all the numbers together, and all the variables

55y+1=0

We move all terms containing y to the left, all other terms to the right

55y=-1

y=-1/55

y=-1/55

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