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7+3/y=y-6
We move all terms to the left:
7+3/y-(y-6)=0
Domain of the equation: y!=0We get rid of parentheses
y∈R
3/y-y+6+7=0
We multiply all the terms by the denominator
-y*y+6*y+7*y+3=0
We add all the numbers together, and all the variables
13y-y*y+3=0
Wy multiply elements
-1y^2+13y+3=0
a = -1; b = 13; c = +3;
Δ = b2-4ac
Δ = 132-4·(-1)·3
Δ = 181
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{181}}{2*-1}=\frac{-13-\sqrt{181}}{-2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{181}}{2*-1}=\frac{-13+\sqrt{181}}{-2} $
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