7+3=r-4(2+r)

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Solution for 7+3=r-4(2+r) equation: 



7+3=r-4(2+r)

We move all terms to the left:

7+3-(r-4(2+r))=0

We add all the numbers together, and all the variables

-(r-4(r+2))+7+3=0

We add all the numbers together, and all the variables

-(r-4(r+2))+10=0



We calculate terms in parentheses: -(r-4(r+2)), so:

r-4(r+2)

We multiply parentheses

r-4r-8

We add all the numbers together, and all the variables

-3r-8

Back to the equation:

-(-3r-8)



We get rid of parentheses

3r+8+10=0

We add all the numbers together, and all the variables

3r+18=0

We move all terms containing r to the left, all other terms to the right

3r=-18

r=-18/3

r=-6

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