7+3x-3(x+1)=x+2(x-4)

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Solution for 7+3x-3(x+1)=x+2(x-4) equation: 



7+3x-3(x+1)=x+2(x-4)

We move all terms to the left:

7+3x-3(x+1)-(x+2(x-4))=0

We multiply parentheses

3x-3x-(x+2(x-4))-3+7=0



We calculate terms in parentheses: -(x+2(x-4)), so:

x+2(x-4)

We multiply parentheses

x+2x-8

We add all the numbers together, and all the variables

3x-8

Back to the equation:

-(3x-8)



We add all the numbers together, and all the variables

-(3x-8)+4=0

We get rid of parentheses

-3x+8+4=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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