7+3x=4(2+3/4x

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Solution for 7+3x=4(2+3/4x equation: 



7+3x=4(2+3/4x

We move all terms to the left:

7+3x-(4(2+3/4x)=0



Domain of the equation: 4x)+7!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3x-(4(3/4x+2)+7=0

We multiply all the terms by the denominator


3x*4x+2)+7-(4(3=0

We add all the numbers together, and all the variables

3x*4x=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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