7+3x=4(2+34x)

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Solution for 7+3x=4(2+34x) equation: 



7+3x=4(2+34x)

We move all terms to the left:

7+3x-(4(2+34x))=0

We add all the numbers together, and all the variables

3x-(4(34x+2))+7=0



We calculate terms in parentheses: -(4(34x+2)), so:

4(34x+2)

We multiply parentheses

136x+8

Back to the equation:

-(136x+8)



We get rid of parentheses

3x-136x-8+7=0

We add all the numbers together, and all the variables

-133x-1=0

We move all terms containing x to the left, all other terms to the right

-133x=1

x=1/-133

x=-1/133

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