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7+3x=x4(2+x)
We move all terms to the left:
7+3x-(x4(2+x))=0
We add all the numbers together, and all the variables
3x-(x4(x+2))+7=0
We calculate terms in parentheses: -(x4(x+2)), so:
x4(x+2)
We multiply parentheses
x^5+2x^4
We do not support expression: x^5
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