7+3y-1=y+12

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Solution for 7+3y-1=y+12 equation: 



7+3y-1=y+12

We move all terms to the left:

7+3y-1-(y+12)=0

We add all the numbers together, and all the variables

3y-(y+12)+6=0

We get rid of parentheses

3y-y-12+6=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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