7+3y-3=8y+28-2y

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Solution for 7+3y-3=8y+28-2y equation:



7+3y-3=8y+28-2y
We move all terms to the left:
7+3y-3-(8y+28-2y)=0
We add all the numbers together, and all the variables
3y-(6y+28)+7-3=0
We add all the numbers together, and all the variables
3y-(6y+28)+4=0
We get rid of parentheses
3y-6y-28+4=0
We add all the numbers together, and all the variables
-3y-24=0
We move all terms containing y to the left, all other terms to the right
-3y=24
y=24/-3
y=-8

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