7+3y=(3y-8)/7

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Solution for 7+3y=(3y-8)/7 equation: 



7+3y=(3y-8)/7

We move all terms to the left:

7+3y-((3y-8)/7)=0

We multiply all the terms by the denominator


3y*7)-((3y-8)+7*7)=0

We add all the numbers together, and all the variables

3y*7)-((3y-8)=0

Wy multiply elements

21y^2=0

a = 21; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·21·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{42}=0$

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