7+3z+32=z+63+8

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Solution for 7+3z+32=z+63+8 equation: 



7+3z+32=z+63+8

We move all terms to the left:

7+3z+32-(z+63+8)=0

We add all the numbers together, and all the variables

3z-(z+71)+7+32=0

We add all the numbers together, and all the variables

3z-(z+71)+39=0

We get rid of parentheses

3z-z-71+39=0

We add all the numbers together, and all the variables

2z-32=0

We move all terms containing z to the left, all other terms to the right

2z=32

z=32/2

z=16

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